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Question Number 89599 by 20000193 last updated on 18/Apr/20

Commented by john santu last updated on 18/Apr/20

$$4a)\tan (A+C)=\frac{\tan A+\tan C}{1-\tan A.\tan C}$$$$case\left(1\right)=\frac{\frac{1}{\sqrt{3}}+\sqrt{3}}{1-\frac{1}{\sqrt{3}}.\sqrt{3}}=\mathrm{\infty }\left(undefined\right)$$$$case\left(2\right)=\frac{\frac{1}{\sqrt{3}}-\sqrt{3}}{1+\frac{1}{\sqrt{3}}.\sqrt{3}}=\frac{-2}{2\sqrt{3}}=-\frac{1}{\sqrt{3}}$$$$case\left(3\right)=\frac{\frac{1}{\sqrt{3}}+\sqrt{3}}{1+\frac{1}{\sqrt{3}}.\sqrt{3}}=\frac{4}{2\sqrt{3}}=\frac{2}{\sqrt{3}}$$$$case\left(4\right)=case\left(1\right)undefined$$

Commented by mr W last updated on 18/Apr/20

$$to20000193:$$$$please{don}^{\prime }tmisusethisplatformto$$$$letotherpeopledohomeworkforyou!$$

Commented by mr W last updated on 18/Apr/20

$$ithinkweshouldnotremunerate$$$$peoplewhojustcopyandthrowtheir$$$$homeworkhere,even{don}^{\prime }tmakethe$$$$efforttotypewhereheorshehas$$$$problem,butexpectthatsomebodywill$$$$doallthethingsforhimorher.$$$$$$$$thisforumhelpspeoplewhotryto$$$$helpthemselves!$$

Commented by john santu last updated on 18/Apr/20

$$i^{\prime }msorrysir.$$

Commented by mr W last updated on 18/Apr/20

$$nevermindsir!{it}^{\prime }sjustmyopinion.$$

Commented by Kunal12588 last updated on 18/Apr/20

$$Ijustwanttoknowdoesengineeringmaths$$$$isofthislevel?$$

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