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Question Number 89795 by A8;15: last updated on 19/Apr/20
Answered by MJS last updated on 19/Apr/20
(x2+1)(x+1)2+x2=(x2+x+1)2x2(x2+1)+1=(x2−x+1)(x2+x+1)⇒x2+x+1x2−x+1=x+1xx4−2x3+x2−2x+1=0(x2−2x−x+1)(x2+2x−x+1)=0andthisiseasytosolve
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