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Question Number 89882 by student work last updated on 19/Apr/20

Answered by Joel578 last updated on 19/Apr/20

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{x!(1-x-1)}{(2x-1)x!}=\underset{x\to \mathrm{\infty }}{\lim }\frac{-x}{2x-1}=-\frac{1}{2}$$

Answered by TANMAY PANACEA. last updated on 19/Apr/20

$$\underset{x\to \mathrm{\infty }}{\lim }\frac{x!-(x+1)x!}{(2x-1)x!}$$$$\underset{x\to \mathrm{\infty }}{\lim }\frac{1-x-1}{2x-1}$$$$=\underset{x\to \mathrm{\infty }}{\lim }\frac{-x}{2x-1}=\frac{-1}{2-\frac{1}{x}}=\frac{-1}{2-0}=\frac{-1}{2}$$

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