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Question Number 90055 by awlia last updated on 21/Apr/20

Commented by jagoll last updated on 21/Apr/20

$$\mathrm{vol}=\pi \underset{0}{\stackrel{4}{\int }}{(4\mathrm{x}-{\mathrm{x}}^2)}^2\mathrm{dx}$$$$=\pi {\{-\frac{{\mathrm{x}}^2{(4-\mathrm{x})}^3}{3}-\frac{\mathrm{x}{(4-\mathrm{x})}^4}{6}-\frac{{(4-\mathrm{x})}^5}{60}\}}_0^4$$$$=\frac{4\times 256\pi }{60}=\frac{256\pi }{15}$$

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