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Question Number 90086 by I want to learn more last updated on 21/Apr/20

Commented by I want to learn more last updated on 21/Apr/20

$$\mathrm{Ohh},\mathrm{i}\mathrm{grab}$$

Commented by I want to learn more last updated on 21/Apr/20

$$\mathrm{And}\mathrm{how}\mathrm{is}\mathrm{a}-2\mathrm{b}+\mathrm{c}=0$$

Commented by mr W last updated on 21/Apr/20

$$sumofcoef.=f\left(1\right)$$$$={\{1+{(a-2b+c)}^2\}}^{1973}$$$$={\{1+0^2\}}^{1973}$$$$=1$$

Commented by I want to learn more last updated on 21/Apr/20

$$\mathrm{Sir}\mathrm{why}\mathrm{is}\mathrm{sum}\mathrm{of}\mathrm{coefficient}=1$$

Commented by john santu last updated on 21/Apr/20

$$a,b,careinAPsuchthat$$$$b-a=c-b$$$$2b=a+c$$

Commented by mr W last updated on 21/Apr/20

$$\mathrm{why}the\mathrm{sum}\mathrm{of}all\mathrm{coefficient}s=f\left(1\right)?$$$$f\left(x\right)=\underset{k=0}{\sum ^n}{a}_k{x}^k$$$$sumofallcoef.=\underset{k=0}{\sum ^n}{a}_k$$$$wegetitwhenweputx=1:$$$$f\left(1\right)=\underset{k=0}{\sum ^n}{a}_k{1}^k=\underset{k=0}{\sum ^n}{a}_k$$

Commented by I want to learn more last updated on 21/Apr/20

$$\mathrm{Thanks}\mathrm{sir}$$

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