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Question Number 90160 by A8;15: last updated on 21/Apr/20

Answered by TANMAY PANACEA. last updated on 21/Apr/20

$$putx=1inRHS$$$$\sqrt{61+6-3}=8$$$$putx=1LHS$$$${16}^{{\left(\frac{1}{\sqrt{2}}\right)}^2}+{16}^{{\left(\frac{1}{\sqrt{2}}\right)}^2}$$$${\left(4^2\right)}^{\frac{1}{2}}+{\left(4^2\right)}^{\frac{1}{2}}=8$$$$trialanderror$$

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