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Question Number 90162 by I want to learn more last updated on 21/Apr/20

Answered by maths mind last updated on 21/Apr/20

$$x=y-1$$$$\iff {(y-2)}^5+{(y+2)}^5=242y$$$$\iff 2y^5+80y^3+160y=242y$$$$\Rightarrow 2y(y^4-40y^2-41)=0$$$$easynow$$

Commented by I want to learn more last updated on 21/Apr/20

$$\mathrm{Thanks}\mathrm{sir}$$

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