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Question Number 9069 by tawakalitu last updated on 16/Nov/16

Commented by RasheedSoomro last updated on 20/Nov/16

$$\{\begin{array}{l}\mathrm{x}+\mathrm{y}=2\\ \mathrm{xy}=4\\ {\mathrm{S}}_{\mathrm{n}}={\mathrm{x}}^{\mathrm{n}}+{\mathrm{y}}^{\mathrm{n}}\end{array}$$$${\mathrm{pS}}_{\mathrm{n}}={\mathrm{S}}_{\mathrm{n}+1}+{\mathrm{qS}}_{\mathrm{n}-1}$$$$\mathrm{p}({\mathrm{x}}^{\mathrm{n}}+{\mathrm{y}}^{\mathrm{n}})=({\mathrm{x}}^{\mathrm{n}+1}+{\mathrm{y}}^{\mathrm{n}+1})+\mathrm{q}({\mathrm{x}}^{\mathrm{n}-1}+{\mathrm{y}}^{\mathrm{n}-1})$$$$\mathrm{Continue}$$

Commented by tawakalitu last updated on 20/Nov/16

$$\mathrm{Thank}\mathrm{you}\mathrm{sir}.\mathrm{i}\mathrm{will}\mathrm{be}\mathrm{expecting}$$

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