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Question Number 9382 by sandipkd@ last updated on 03/Dec/16

Commented by sandipkd@ last updated on 03/Dec/16

$$questionno.9?$$

Answered by mrW last updated on 03/Dec/16

$$\mathrm{question}9:$$$$\mathrm{a}=\frac{\mathrm{dv}}{\mathrm{dt}}=\frac{\mathrm{dv}}{\mathrm{ds}}\times \frac{\mathrm{ds}}{\mathrm{dt}}=\frac{\mathrm{dv}}{\mathrm{ds}}\times \mathrm{v}=4\times \tan 60°=4\sqrt{3}\mathrm{m}/{\mathrm{s}}^2$$$$\Rightarrow \left(\mathrm{a}\right)\mathrm{is}\mathrm{correct}$$$$$$$$\mathrm{question}10:$$$${\mathrm{x}}_1=\frac{1}{2}{\mathrm{gt}}^2$$$$\Rightarrow {2\mathrm{x}}_1={\mathrm{gt}}^2...\left(\mathrm{i}\right)$$$${\mathrm{x}}_1+{\mathrm{x}}_2=\frac{1}{2}\mathrm{g}{\left(2\mathrm{t}\right)}^2={2\mathrm{gt}}^2...\left(\mathrm{ii}\right)$$$$\left(\mathrm{ii}\right)-\left(\mathrm{i}\right)$$$$\Rightarrow {\mathrm{x}}_2-{\mathrm{x}}_1={\mathrm{gt}}^2$$$$\mathrm{t}=\sqrt{\frac{{\mathrm{x}}_2-{\mathrm{x}}_1}{\mathrm{g}}}$$$$\Rightarrow \left(\mathrm{a}\right)\mathrm{is}\mathrm{correct}$$

Commented by sandipkd@ last updated on 03/Dec/16

$$thanksbro$$

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