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Question Number 9404 by alfat123 last updated on 05/Dec/16

Answered by geovane10math last updated on 06/Dec/16

$$\mathrm{I}{\mathrm{can}}^{\prime }\mathrm{t}\mathrm{read}...$$$$f^{\prime }\left(x\right)=2x+2$$$$\int f^{\prime }\left(x\right)dx=\int 2x+2dx=\int 2xdx+\int 2dx$$$$=x^2+2x+C$$$$f\left(x\right)=x^2+2x+C$$$$f\left(2\right)=8+C$$

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