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Question Number 96846 by bobhans last updated on 05/Jun/20
Commented by john santu last updated on 05/Jun/20
[a2x+(2−2a)x2+x4]12⩽12⇔a2+(2−2a).3+15⩽12a2−6a+21−12⩽0a2−6a+9⩽0(a−3)2⩽0;a=3
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