Question and Answers Forum

All Questions      Topic List

Mensuration Questions

Previous in All Question      Next in All Question      

Previous in Mensuration      Next in Mensuration      

Question Number 96866 by bobhans last updated on 05/Jun/20

Commented by john santu last updated on 05/Jun/20

$$\mathrm{ratio}=\frac{4\sqrt{5}\times 4\sqrt{5}}{{\left(4\sqrt{5}\right)}^2+{\left(8\sqrt{5}\right)}^2}$$$$=\frac{{\left(4\sqrt{5}\right)}^2}{{\left(4\sqrt{5}\right)}^2(1+2^2)}=1:5$$

Answered by Sourav mridha last updated on 05/Jun/20

$$\mathit{r}\mathit{a}\mathit{t}\mathit{i}\mathit{o}:\frac{{\left(4\sqrt{5}\right)}^2}{{\left(4\sqrt{5}\right)}^2+{\left(8\sqrt{5}\right)}^2}=\frac{1}{5}$$

Commented by bemath last updated on 05/Jun/20

$$\mathrm{the}\mathrm{first}\mathrm{your}\mathrm{answer}\mathrm{is}$$$$\frac{{\left(4\sqrt{5}\right)}^2}{\sqrt{{\left(4\sqrt{5}\right)}^2+{\left(8\sqrt{5}\right)}^2}}$$

Commented by john santu last updated on 05/Jun/20

$$\mathrm{no}$$

Commented by bemath last updated on 05/Jun/20

$$\mathrm{your}\mathrm{changed}\mathrm{answer}$$

Commented by Sourav mridha last updated on 05/Jun/20

what no!!!!

Commented by Sourav mridha last updated on 05/Jun/20

yeah at first I put √,but when I rechaked it then edited my ans...but then there was no comment...yeah it's okk..just typing error and I often do so..

Commented by bobhans last updated on 05/Jun/20

$$\mathrm{yes}.\mathrm{thank}\mathrm{you}$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com