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Question Number 38515 by Rio Mike last updated on 26/Jun/18

$$Question;$$$$x^3+x^3=$$$$A)x^9$$$$B)x^6$$$$C)x^3$$$$D)1$$$$Giveareasonforyouranswer.$$

Answered by MJS last updated on 26/Jun/18

$$x^3+x^3=x^9\Rightarrow 2x^3=x^9\Rightarrow x=0\vee x^6=2\Rightarrow$$$$\Rightarrow x=0\vee x=\pm \sqrt[6]{2}\vee x=-\frac{\sqrt[6]{2}}{2}\pm \mathrm{i}\frac{\sqrt[6]{2}}{2}\sqrt{3}\vee x=\frac{\sqrt[6]{2}}{2}\pm \mathrm{i}\frac{\sqrt[6]{2}}{2}\sqrt{3}$$$$$$$$x^3+x^3=x^6\Rightarrow 2x^3=x^6\Rightarrow x=0\vee x^3=2\Rightarrow$$$$\Rightarrow x=0\vee x=\sqrt[3]{2}\vee x=-\frac{\sqrt[3]{2}}{2}\pm \mathrm{i}\frac{\sqrt[3]{2}}{2}\sqrt{3}$$$$$$$$x^3+x^3=x^3\Rightarrow x^3=0\Rightarrow x=0$$$$$$$$x^3+x^3=1\Rightarrow x^3=\frac{1}{2}\Rightarrow x=\frac{\sqrt[3]{4}}{2}\vee x=-\frac{\sqrt[3]{4}}{4}\pm \mathrm{i}\frac{\sqrt[3]{4}}{4}\sqrt{3}$$

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