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Question Number 8838 by tawakalitu last updated on 31/Oct/16

$$\mathrm{Show}\mathrm{that}:{\mathrm{e}}^{\mathrm{i}\pi +1}=0$$

Answered by FilupSmith last updated on 31/Oct/16

$$\mathrm{do}\mathrm{you}\mathrm{mean}{e}^{i\pi }+1=0$$$$e^{ix}=\cos \left(x\right)+i\sin \left(x\right)$$$$x=\pi$$$$e^{i\pi }=(-1)+i\left(0\right)$$$$e^{i\pi }=-1$$$$\therefore e^{i\pi }+1=(-1)+1=0$$

Commented by tawakalitu last updated on 31/Oct/16

$$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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