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Question Number 21768 by Tinkutara last updated on 03/Oct/17

$$\mathrm{Six}\mathrm{cards}\mathrm{and}\mathrm{six}\mathrm{envelopes}\mathrm{are}\mathrm{numbered}$$$$1,2,3,4,5,6\mathrm{and}\mathrm{cards}\mathrm{are}\mathrm{to}\mathrm{be}\mathrm{placed}$$$$\mathrm{in}\mathrm{envelopes}\mathrm{so}\mathrm{that}\mathrm{each}\mathrm{envelope}$$$$\mathrm{contains}\mathrm{exactly}\mathrm{one}\mathrm{card}\mathrm{and}\mathrm{no}\mathrm{card}$$$$\mathrm{is}\mathrm{placed}\mathrm{in}\mathrm{the}\mathrm{envelope}\mathrm{bearing}\mathrm{the}$$$$\mathrm{same}\mathrm{number}\mathrm{and}\mathrm{moreover}\mathrm{the}\mathrm{card}$$$$\mathrm{numbered}1\mathrm{is}\mathrm{always}\mathrm{placed}\mathrm{in}\mathrm{envelope}$$$$\mathrm{numbered}2.\mathrm{Then}\mathrm{the}\mathrm{number}\mathrm{of}\mathrm{ways}$$$$\mathrm{it}\mathrm{can}\mathrm{be}\mathrm{done}\mathrm{is}$$

Commented by mrW1 last updated on 09/Oct/17

$$153?$$

Commented by Tinkutara last updated on 10/Oct/17

$$\mathrm{No}.$$

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