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Question Number 161884 by HongKing last updated on 23/Dec/21

$$\mathrm{Solve}\mathrm{for}\mathrm{real}\mathrm{numbers}:$$$$\sqrt[7]{2^{\mathbf{x}}+2^{-1}}=1+\sqrt[7]{2^{\mathbf{x}}-2^{-1}}$$

Commented by mr W last updated on 23/Dec/21

$$\sqrt[7]{2^x+\frac{1}{2}}=1+\sqrt[7]{2^x-\frac{1}{2}}$$$$1=1+0?$$$$\Rightarrow 2^x=\frac{1}{2}✓$$$$\Rightarrow x=-1$$

Commented by HongKing last updated on 25/Dec/21

$$\mathrm{thank}\mathrm{you}\mathrm{my}\mathrm{dear}\mathrm{Sir}$$

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