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Question Number 116092 by Engr_Jidda last updated on 30/Sep/20

$$Solveforxandyif$$$$x^y=36$$

Commented by MJS_new last updated on 30/Sep/20

$$x,y\in \mathbb{Z}?$$

Commented by Engr_Jidda last updated on 30/Sep/20

$$yessir$$

Answered by MJS_new last updated on 30/Sep/20

$$36=2^2{3}^2$$$$36={36}^1={(\pm 6)}^2$$$$\left(\begin{array}{c}x\\ y\end{array}\right)\in \{\left(\begin{array}{c}-6\\ 2\end{array}\right),\left(\begin{array}{c}6\\ 2\end{array}\right),\left(\begin{array}{c}36\\ 1\end{array}\right)\}$$

Commented by Engr_Jidda last updated on 30/Sep/20

$$thankyousir$$

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