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Question Number 6802 by FilupSmith last updated on 27/Jul/16
Solveforxx(x2+1)2=1
Commented by Yozzii last updated on 28/Jul/16
x(x4+2x2+1)=1x5+2x3+x−1=0(∗)xmustbesuchthat0<x<1for(∗)tobetrue.ByNewton−Raphsonmethod,x≈0.5698to4d.p.Graphically,(∗)hasonlyonerealroot.Theremainingrootsoccurinconjugatepairs,forthecoefficientsof(∗)areallreal.
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