The block of mass 2 kg and 3 kg are placed one over the other. The contact surfaces are rough with coefficient of friction μ_1 = 0.2, μ_2 = 0.06. A force F = (1/2)t N (where t is in second) is applied on upper block in the direction. (Given that g = 10 m/s^2 ) 1. The relative slipping between the blocks occurs at t = 2. Friction force acting between the two blocks at t = 8 s 3. The acceleration time graph for 3 kg block is


Question and Answers Forum

All Questions Topic List
Others Questions
Previous in All Question Next in All Question
Previous in Others Next in Others
Question Number 21670 by Tinkutara last updated on 30/Sep/17

$The block of mass 2 kg and 3 kg are$ $placed one over the other . The contact$ $surfaces are rough with coefficient of$ $friction μ_{1} = 0.2, μ_{2} = 0.06 . A force F =$ $\frac{1}{2} t N (where t is in second) is applied$ $on upper block in the direction . (Given$ $that g = 10 m / s^{2})$ $1 . The relative slipping between the$ $blocks occurs at t =$ $2 . Friction force acting between the two$ $blocks at t = 8 s$ $3 . The acceleration time graph for 3 kg$ $block is$
Commented by Tinkutara last updated on 30/Sep/17

	Answered by ajfour last updated on 30/Sep/17

	$A t t = 6 s, F = 3 N$ $f_{1} = 3 N b a c k w a r d o n 2 k g a n d$ $f o r w a r d o n 3 k g .$ $f_{2} = 3 N (l i m i t i n g v a l u e) b a c k w a r d$ $o n 3 k g .$ $\Rightarrow o n s e t o f a c c e l e r a t i o n a t t = 6 s$ $A t t = 8 s, F = 4 N$ $f_{1} - f_{2} = 3 a \Rightarrow f_{1} - 3 = 3 a . . . (i)$ $F - f_{1} = 2 a \Rightarrow 4 - f_{1} = 2 a . . . . (i i)$ $s o 2 f_{1} - 6 = 12 - 3 f_{1}$ $\Rightarrow 5 f_{1} = 18; f_{1} = 3.6 N .$
	Commented by Tinkutara last updated on 30/Sep/17

	$Thank you very much Sir!$ $Can you answer other 2 ? Because they$ $do not match answer .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum