The distance moved by a particle in t seconds is given by s= t^3 + 3t + 1 where s is in metres.Find the velocity and Asseleration after 3 seconds. Show all steps with short statements on how the answers are gotten.


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Question Number 37860 by Rio Mike last updated on 18/Jun/18

$T h e d i s t a n c e m o v e d b y a p a r t i c l e$ $i n t s e c o n d s i s g i v e n b y$ $s = t^{3} + 3 t + 1 w h e r e s i s i n$ $m e t r e s . F i n d t h e v e l o c i t y a n d$ $A s s e l e r a t i o n a f t e r 3 s e c o n d s .$ $S h o w a l l s t e p s w i t h s h o r t s t a t e m e n t s$ $o n h o w t h e a n s w e r s a r e g o t t e n .$
	Answered by MrW3 last updated on 18/Jun/18

	$v (t) = \frac{d s}{d t} = 3 t^{2} + 3$ $a (t) = \frac{d v}{d t} = 6 t$ $a t t = 3 s e c :$ $v = 3 \times 3^{2} + 3 = 30 m / s$ $a = 6 \times 3 = 18 m / s^{2}$
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