The function of f and g are defined by f:g→(x/(bx−2)), x ≠ (2/b) and b ≠ 0, where a and b are real numbers g:x →2x−11 (a) If f(2)= ((-1)/2) and f^(−1) (1) = -1, find a and b and write down the expression for f in terms of x (b) Find the value of x for which fg(x)= ((-1)/2)


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Question Number 85500 by oustmuchiya@gmail.com last updated on 22/Mar/20

$T h e f u n c t i o n o f f a n d g a r e d e f i n e d b y f : g \to \frac{x}{b x - 2}, x \neq \frac{2}{b} a n d b \neq 0, w h e r e a a n d b a r e r e a l n u m b e r s g : x \to 2 x - 11$ $(a) I f f (2) = \frac{- 1}{2} a n d f^{- 1} (1) = - 1, f i n d a a n d b a n d w r i t e d o w n t h e e x p r e s s i o n f o r f i n t e r m s o f x$ $(b) F i n d t h e v a l u e o f x f o r w h i c h fg (x) = \frac{- 1}{2}$
	Answered by john santu last updated on 22/Mar/20

	$n o t h i n g a i n y o u r q u e s t i o n$
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