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Question Number 20326 by kkr1729 last updated on 25/Aug/17

$$\mathrm{The}\mathrm{number}\mathrm{of}\mathrm{positive}\mathrm{inegral}$$$$\mathrm{solutions}\mathrm{of}abc=30\mathrm{is}$$

Commented by Tinkutara last updated on 25/Aug/17

$$30=2\times 3\times 5=8\mathrm{factors}$$$$\mathrm{Required}\mathrm{number}\mathrm{of}\mathrm{ways}={}^8{C}_3=56$$$$\mathrm{Ordered}\mathrm{triplets}={}^8{P}_3=336$$

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