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Question Number 64414 by Yitagesuweldesenbet@gmail. Com last updated on 17/Jul/19
Thenumberofpositiveintegerssatisfyingtheinequalityn+1Cn−2−n+1Cn−1⩽100is____.
Answered by mr W last updated on 17/Jul/19
n+1Cn−2=n+1C3=(n+1)n(n−1)3!n+1Cn−1=n+1C2=(n+1)n2!(n+1)n(n−1)3!−(n+1)n2!⩽100(n+1)n(n−4)⩽600withn=9:LHD=10×9×5=450<600withn=10:LHD=11×10×6=660>600⇒2⩽n⩽9
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