The side of a square is increasing at a rate of 0.1cms^(−1) . Find the rate of increase of the perimeter of the square when the length of side is 4cm.


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Question Number 37795 by Rio Mike last updated on 17/Jun/18

$T h e s i d e o f a s q u a r e i s i n c r e a s i n g$ $a t a r a t e o f 0.1 {c m s}^{- 1} . F i n d t h e$ $r a t e o f i n c r e a s e o f t h e p e r i m e t e r$ $o f t h e s q u a r e w h e n t h e l e n g t h o f$ $s i d e i s 4 c m .$
	Answered by tanmay.chaudhury50@gmail.com last updated on 18/Jun/18

	$p = 4 a$ $\frac{d p}{d t} = 4 \frac{d a}{d t} p = p e r i m e t e r a = s i d e o f s q u a r e$ $\frac{d p}{d t} = 4 \times 0.1 = 0.4 c m / s e c$
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