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Question Number 15610 by RasheedSoomro last updated on 12/Jun/17

$$\mathrm{The}\mathrm{temperature}\mathrm{of}\mathrm{some}100\mathrm{litres}$$$$\mathrm{is}80°\mathrm{C}.10\mathrm{litres}\mathrm{water},\mathrm{whose}\mathrm{temperature}$$$$\mathrm{is}100°\mathrm{C}\mathrm{is}\mathrm{mixed}\mathrm{in}\mathrm{it}.\mathrm{What}\mathrm{will}\mathrm{be}\mathrm{the}$$$$\mathrm{temperature}\mathrm{of}\mathrm{mixed}\mathrm{water}?$$

Commented by RasheedSoomro last updated on 12/Jun/17

$$\mathrm{Thanks}\mathrm{Sir}!$$

Commented by mrW1 last updated on 12/Jun/17

$$\mathrm{x}=\frac{100\times 80+10\times 100}{110}$$$$=\frac{9000}{110}=81.8°\mathrm{C}$$

Commented by mrW1 last updated on 12/Jun/17

$$\mathrm{our}\mathrm{experience}\mathrm{tells}\mathrm{us}\mathrm{the}\mathrm{mixed}$$$$\mathrm{water}\mathrm{must}\mathrm{be}>80°\mathrm{and}<100°\mathrm{warm}.$$

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