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Question Number 18742 by Tinkutara last updated on 31/Jul/17
Thevalueofcot16°cot44°+cot44°cot76°−cot76°cot16°is
Answered by Tinkutara last updated on 31/Jul/17
3+cot76°cot16°cot76°+cot16°=3sin76°sin16°+cos76°cos16°sin(76°+16°)=2sin76°sin16°+cos(76°−16°)sin92°=cos60°−cos92°+cos60°sin92°=1−cos92°sin92°=tan46°=cot44°Now,3+cot76°cot16°cot76°+cot16°=cot44°cot16°cot44°+cot44°cot76°−cot76°cot16°=3
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