Two passenger trains, A and B, 450km apart, start to move towards each other at the same time and meet after 2 hours. If train B, travels (8/7) as fast as train A, find the speed of each train.


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Question Number 60143 by pete last updated on 18/May/19

$Two passenger trains, A and B, 450 km apart,$ $start to move towards each other at the$ $same time and meet after 2 hours . If train B,$ $travels \frac{8}{7} as fast as train A, find the speed$ $of each train .$
	Answered by tanmay last updated on 18/May/19

	$s p e e d o f t r a i n A = 7 v k m / h r s$ $s p e e d o c t r a i n B = \frac{8}{7} \times 7 v = 8 v k m / h r s$ $s o \frac{450}{7 v + 8 v} = 2$ $\frac{30}{v} = 2 \to v = 15 k m / h r s$ $s p e e d o f A = 7 \times 15 = 105 k m / h r s$ $s p e e d o f B = 8 \times 15 = 120 k m / h r s$
	Commented by pete last updated on 18/May/19

	$Thanks very much sir, but how is speed$ $of train A = 7 v k m / h r ?$
	Commented by tanmay last updated on 18/May/19

	$a n s w e r i s c o r r e c t o r n o t . . .$
	Commented by tanmay last updated on 18/May/19

	$i h a v e t a k e n s p e e d A = 7 v b e c a u s e i c a n c a c u l a t e$ $e a s i l y t o f i n d s p e e d o f B$ $7 v \times \frac{8}{7} = 8 v$ $y o u c a n t a k e s p e e d f o r A = v$ $s p e e d o f B = \frac{8}{7} \times v$ $\frac{450}{v + \frac{8 v}{7}} = 2$ $\frac{450 \times 7}{15 v} = 2$ $2 v = 30 \times 7$ $v = 105 k m / h r \to s p e e d o f A$ $105 \times \frac{8}{7} . = 15 \times 8 = 120 k m / h r s p e e d o f B$
	Commented by pete last updated on 18/May/19

	$Ow its correct, only wanted to get clarification$ $I understand now . Thanks gain .$
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