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Question Number 178013 by Spillover last updated on 12/Oct/22

$$\mathrm{Using}\mathrm{Electronic}\mathrm{diagrams}\mathrm{show}$$$$\mathrm{the}\mathrm{bonding}\mathrm{in}\mathrm{the}\mathrm{following}$$$$\left(\mathrm{a}\right)\mathrm{Magnesium}\mathrm{chloride}$$$$\left(\mathrm{b}\right)\mathrm{Sodium}\mathrm{chloride}$$

Answered by Spillover last updated on 12/Oct/22

Answered by Spillover last updated on 12/Oct/22

Answered by Spillover last updated on 12/Oct/22

Answered by Spillover last updated on 12/Oct/22

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