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Question Number 178448 by Spillover last updated on 16/Oct/22

$$\mathrm{Using}\mathrm{the}\mathrm{algebra}\mathrm{propositions}$$$$\mathrm{simplify}$$$$(\mathrm{p}\leftrightarrow \mathrm{q})\to (\mathrm{p}\to \mathrm{q})$$

Answered by greougoury555 last updated on 16/Oct/22

$$[(p\to q)\wedge (q\to p)]\to (p\to q)$$$$=[(p\wedge \sim q)\vee (q\wedge \sim p)]\vee (\sim p\vee q)$$$$=(p\wedge \sim q)\vee (\sim p\wedge q)\vee (\sim p\vee q)$$$$=T$$

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