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Question Number 75518 Answers: 1 Comments: 0

Question Number 75260 Answers: 0 Comments: 0

Question Number 74579 Answers: 0 Comments: 0

find the gradient of scalar point function being expressed in term of scalar triple product as u=(a^ ,b^ ,c^ )=a^ .b^ ×c^

$f i n d t h e g r a d i e n t o f s c a l a r p o i n t f u n c t i o n b e i n g e x p r e s s e d i n t e r m o f s c a l a r t r i p l e p r o d u c t a s u = (\bar{a}, \bar{b}, \bar{c}) = \bar{a} . \bar{b} \times \bar{c}$

Question Number 73940 Answers: 1 Comments: 0

Question Number 73084 Answers: 1 Comments: 0

Question Number 72832 Answers: 1 Comments: 1

In a parallelogram OABC, OA^⇁ =a^(−⇁) , OC^→ =c^→ , D is a point such that AD^→ :DB^→ =1:2 Express the following in terms of a and c (i)CB^→ (ii)BC^→ (iii)AB^→ (iv) AD^→ (v)OD^→ (vi)DC^→

$I n a p a r a l l e l o g r a m O A B C, O \overset{⇁}{A} = \overset{- ⇁}{a},$ $O \vec{C} = \vec{c}, D i s a p o i n t s u c h t h a t A \vec{D} : D \vec{B} = 1 : 2$ $E x p r e s s t h e f o l l o w i n g i n t e r m s o f a a n d c$ $(i) C \vec{B} (i i) B \vec{C} (i i i) A \vec{B} (i v) A \vec{D} (v) O \vec{D}$ $(v i) D \vec{C}$

Question Number 72773 Answers: 1 Comments: 2

Question Number 71986 Answers: 1 Comments: 0

Question Number 69620 Answers: 0 Comments: 1

Question Number 69585 Answers: 0 Comments: 0

Question Number 68608 Answers: 0 Comments: 0

Question Number 68591 Answers: 0 Comments: 6

Question Number 68315 Answers: 0 Comments: 1

∫(((x^(−3) +2x−4)/x))

$\int (\frac{x^{- 3} + 2 x - 4}{x})$

Question Number 66971 Answers: 0 Comments: 3

∫(dx/(x(√(x^2 +x+1 ))))=? please help

$\int \frac{dx}{x \sqrt{x^{2} + x + 1}} = ?$ $p l ease help$

Question Number 64348 Answers: 1 Comments: 0

the vectors a and b are such that ∣a∣ =3 , ∣b∣=5 and a.b=−14 find ∣a−b∣

$t h e v e c t o r s a a n d b a r e s u c h t h a t ∣ a ∣ = 3, ∣ b ∣= 5 a n d a . b = - 14$ $f i n d ∣ a - b ∣$

Question Number 64085 Answers: 0 Comments: 0

please just read equation of a line and a plane in vectors. i don′t understand (r−a)×b=0 ??

$p l e a s e j u s t r e a d e q u a t i o n o f a l i n e a n d a p l a n e i n v e c t o r s .$ $i {d o n}^{'} t u n d e r s t a n d$ $(r - a) \times b = 0 ? ?$

Question Number 63427 Answers: 0 Comments: 4

(1) A plane contains the lines ((x+1)/2)=((4−y)/2)=((z−2)/3) and r= (2i+2j + 12k)+t(−i+2j +4k). find (a) the angle between these lines. (b) A cartesian equation of the plane. (2) Given the lines l_1 :((x−10)/3)=((y−1)/1)=((z−9)/4) l_2 :r=(−9j+13k)+μ(i+2j−3k) where μ is a parameter; l_3 :((x+10)/4)=((y+5)/3)=((z+4)/1). a) show that the point (4,−1,1) is common to l_1 and l_2 . Find b) the point of intersection of l_2 and l_3 . c) A vector parametric equation of the plane containing the lines l_2 and l_3 . sir Forkum Michael

$(1) A p l a n e c o n t a i n s t h e l i n e s \frac{x + 1}{2} = \frac{4 - y}{2} = \frac{z - 2}{3} a n d$ $r = (2 i + 2 j + 12 k) + t (- i + 2 j + 4 k) . f i n d$ $(a) t h e a n g l e b e t w e e n t h e s e l i n e s .$ $(b) A c a r t e s i a n e q u a t i o n o f t h e p l a n e .$ $(2) G i v e n t h e l i n e s l_{1} : \frac{x - 10}{3} = \frac{y - 1}{1} = \frac{z - 9}{4} l_{2} : r = (- 9 j + 13 k) + μ (i + 2 j - 3 k)$ $w h e r e μ i s a p a r a m e t e r; l_{3} : \frac{x + 10}{4} = \frac{y + 5}{3} = \frac{z + 4}{1} .$ $a) s h o w t h a t t h e p o i n t (4, - 1, 1) i s c o m m o n t o l_{1} a n d l_{2} . F i n d$ $b) t h e p o i n t o f i n t e r s e c t i o n o f l_{2} a n d l_{3} .$ $c) A v e c t o r p a r a m e t r i c e q u a t i o n o f t h e p l a n e c o n t a i n i n g t h e$ $l i n e s l_{2} a n d l_{3} .$ $s i r F o r k u m M i c h a e l$

Question Number 62624 Answers: 2 Comments: 0

Question Number 62622 Answers: 0 Comments: 0

Question Number 62585 Answers: 1 Comments: 0

find the resultant force of a system of three forces O^− P^→ =9N,O^− R^→ =10N and O^− Q^→ 10N acting at point O where angle POR is 135°,angle POQ is 135° and QOR is 90°

$f i n d t h e r e s u l t a n t f o r c e o f a s y s t e m$ $o f t h r e e f o r c e s \bar{O} \vec{P} = 9 N, \bar{O} \vec{R} = 10 N a n d \bar{O} \vec{Q} 10 N$ $a c t i n g a t p o i n t O w h e r e a n g l e P O R i s$ $135 °, a n g l e P O Q i s 135 ° a n d Q O R i s$ $90 °$

Question Number 62583 Answers: 1 Comments: 0

find the vector sum of two vectors of magnitude of 7 and 8 making an angle of 120° to each other

$f i n d t h e v e c t o r s u m o f t w o v e c t o r s$ $o f m a g n i t u d e o f 7 a n d 8 m a k i n g a n$ $a n g l e o f 120 ° t o e a c h o t h e r$

Question Number 62587 Answers: 1 Comments: 1

three forces having equal magnitude s of 10N,20N and 30N make angles of 30°,120° and 210° respectively with the positive direction of the x axis. By scale drawing find the magnitude and the direction of the resultant force

$t h r e e f o r c e s h a v i n g e q u a l m a g n i t u d e$ $s o f 10 N, 20 N a n d 30 N m a k e a n g l e s$ $o f 30 °, 120 ° a n d 210 ° r e s p e c t i v e l y w i t h$ $t h e p o s i t i v e d i r e c t i o n o f t h e x a x i s .$ $B y s c a l e d r a w i n g f i n d t h e m a g n i t u d e$ $a n d t h e d i r e c t i o n o f t h e r e s u l t a n t$ $f o r c e$

Question Number 62130 Answers: 1 Comments: 0

(√(α^2 −β^2 )) simplify

$\sqrt{α^{2} - β^{2}}$ $s i m p l i f y$

Question Number 62034 Answers: 0 Comments: 0

calculate ∫_0 ^1 (x^3 /(2e^(−x) −x^2 +2x−2)) dx

$c a l c u l a t e \int_{0}^{1} \frac{x^{3}}{2 e^{- x} - x^{2} + 2 x - 2} d x$

Question Number 61823 Answers: 1 Comments: 0

If D,E and F are midpoints of the sides BC,CA and AB respectively of the △ABC and O be any point.Prove that OA^→ + OB^→ +OC^→ =OD^→ +OE^→ +OF^→

$I f D, E a n d F a r e m i d p o i n t s o f t h e s i d e s$ $B C, C A a n d A B r e s p e c t i v e l y o f t h e △ A B C$ $a n d O b e a n y p o i n t . P r o v e t h a t$ $O \vec{A} + O \vec{B} + O \vec{C} = O \vec{D} + O \vec{E} + O \vec{F}$

Question Number 60628 Answers: 0 Comments: 0

Who know dynamics about?

$W h o k n o w d y n a m i c s a b o u t ?$

Pg 5 Pg 6 Pg 7 Pg 8 Pg 9 Pg 10 Pg 11 Pg 12 Pg 13 Pg 14

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