When rolling 2 dice what is the probability your not getting 2?


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Question Number 89660 by Mr.Panoply last updated on 18/Apr/20

$W h e n r o l l i n g 2 d i c e w h a t i s t h e p r o b a b i l i t y$ $y o u r n o t g e t t i n g 2 ?$
Commented by john santu last updated on 18/Apr/20

$g e t t i n g 2 ? 2 w h a t ?$
Commented by Mr.Panoply last updated on 18/Apr/20

$r e p h r a s e . p r o b a b i l i t y n o d i e s h o w s a 2 .$
Commented by mr W last updated on 18/Apr/20

$t o t a l l y 6 \times 6 = 36 p o s s i b i l i t i e$ $o n e ‘ ‘ 2^{″} : 2 \times 5 = 10 p o s s i b i l i t i e s$ $t w o ‘ ‘ 2^{″} : 1 p o s s i b i l i t y$ $n o ‘ ‘ 2^{″} : 36 - 10 - 1 = 25$ $\Rightarrow p = \frac{25}{36}$
	Answered by Joel578 last updated on 18/Apr/20

	$(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)$ $(1, 2), (3, 2), (4, 2), (5, 2), (6, 2)$ $Getting number 2 = \frac{11}{36}$ $Not getting number 2 = 1 - \frac{11}{36} = \frac{25}{36}$
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