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Question Number 6792 by Tawakalitu. last updated on 26/Jul/16

When the price of egg was raised by #2 an egg, the number of eggs which can be bought for #120 is reduced by #5. What is the present price of the egg.

You can't use 'macro parameter character #' in math modeYou can't use 'macro parameter character #' in math modepresentpriceoftheegg.

Commented by Yozzii last updated on 27/Jul/16

Let price per egg be p=p_0 +2 (p_0 is initial price). Let n(s,p) be number of eggs that can be bought for $s under rate $p. ∴ n(120,p_0 )=n_0 =((120)/p_0 )=((120)/(p−2)) But, n(120,p)=n(#120,p_0 )−5=((120)/p_0 )−5 or n(120,p)=((120)/(p−2))−5=((120−5p+10)/(p−2))=((130−5p)/(p−2)) But, n(120,p)=((120)/p). ⇒((130−5p)/(p−2))=((120)/p)⇒130p−5p^2 =120p−240 5p^2 −10p−240=0 p=((10±(√(100−4×5×(−240))))/(10)) p=((10±70)/(10))=1±7 p>0⇒p=8

Letpricepereggbep=p0+2(p0isinitialprice).Letn(s,p)benumberofeggsthatcanbeboughtfor$sunderrate$p.∴n(120,p0)=n0=120p0=120p−2You can't use 'macro parameter character #' in math modeorn(120,p)=120p−2−5=120−5p+10p−2=130−5pp−2But,n(120,p)=120p.⇒130−5pp−2=120p⇒130p−5p2=120p−2405p2−10p−240=0p=10±100−4×5×(−240)10p=10±7010=1±7p>0⇒p=8

Commented by Tawakalitu. last updated on 27/Jul/16

Thanks so much for your help

Thankssomuchforyourhelp

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