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Question Number 177742 by Spillover last updated on 08/Oct/22

$$\mathrm{Write}\mathrm{the}\mathrm{chemical}\mathrm{formular}\mathrm{of}$$$$\mathrm{the}\mathrm{following}$$$$\left(\mathrm{a}\right)\mathrm{Magnessium}\mathrm{nitrate}$$$$\left(\mathrm{b}\right)\mathrm{Allumiun}\mathrm{sulphate}$$$$\left(\mathrm{c}\right)\mathrm{carbondioxide}$$$$\left(\mathrm{d}\right)\mathrm{Calcium}\mathrm{Oxide}$$$$\left(\mathrm{e}\right)\mathrm{Zinc}\mathrm{carbonate}$$$$\left(\mathrm{f}\right)\mathrm{Lead}\mathrm{Oxide}$$$$\left(\mathrm{g}\right)\mathrm{Ammonium}\mathrm{Hydrogen}\mathrm{carbonate}$$$$$$

Answered by a.lgnaoui last updated on 08/Oct/22

$$\left(a\right)\mathrm{Magnesium}\mathrm{Nitrate}\mathrm{or}\left(\mathrm{N}itatedemagnesium\right)$$$$\mathrm{Mg}{\left({\mathrm{NO}}_3\right)}_2\left[{\mathrm{Mg}}^{2+}{2\mathrm{NO}}_3^{-}\right]$$$$\left(\mathrm{b}\right)\mathrm{Aluminium}\mathrm{Sulfate}\left(\mathrm{S}ulfatedaluninium\right)$$$${\mathrm{AL}}_2{\left({\mathrm{SO}}_4\right)}_3\left[{2\mathrm{AL}}^{3+}{3\mathrm{SO}}_4^{2-}\right]$$

Answered by Tawa11 last updated on 08/Oct/22

$$\left(\mathrm{a}\right)\mathrm{Mg}{\left({\mathrm{NO}}_3\right)}_2$$$$\left(\mathrm{b}\right){\mathrm{Al}}_2{\left({\mathrm{SO}}_4\right)}_3$$$$\left(\mathrm{c}\right){\mathrm{CO}}_2$$$$\left(\mathrm{d}\right)\mathrm{CaO}$$$$\left(\mathrm{e}\right){\mathrm{ZnCO}}_3$$$$\left(\mathrm{f}\right)\mathrm{PbO}$$$$\left(\mathrm{g}\right){\mathrm{NH}}_4{\mathrm{HCO}}_3$$

Commented by Spillover last updated on 08/Oct/22

$$\mathrm{thank}\mathrm{you}$$

Answered by Spillover last updated on 09/Oct/22

$$\left(\mathrm{a}\right)\mathrm{Magnessium}\mathrm{nitrate}$$$$\mathrm{Step}1$$$$\mathrm{Mg}{\mathrm{NO}}_3$$$$\mathrm{step}2$$$${\mathrm{Mg}}^{2+}{\mathrm{NO}}_3^{-}$$$$\mathrm{step}3$$$${\mathrm{Mg}}^{2+\curvearrowright }{\mathrm{NO}}_3^{\stackrel{\curvearrowleft }{-}}$$$$\mathrm{Mg}{\left({\mathrm{NO}}_3\right)}_2$$$$$$

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