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Question Number 151070 by mathdanisur last updated on 18/Aug/21

$$\mathrm{a}+\mathrm{b}+\mathrm{c}=30\mathrm{and}\mathrm{a};\mathrm{b};\mathrm{c}>0$$$$\mathrm{find}\mathrm{the}\mathrm{minimum}\mathrm{value}\mathrm{of}$$$$\frac{1}{\mathrm{a}}+\frac{1}{\mathrm{b}}+\frac{1}{\mathrm{c}}$$

Commented by john_santu last updated on 18/Aug/21

$$\frac{1}{\mathrm{a}}+\frac{1}{\mathrm{b}}+\frac{1}{\mathrm{c}}⩾\frac{{(1+1+1)}^2}{\mathrm{a}+\mathrm{b}+\mathrm{c}}=\frac{9}{30}=\frac{3}{10}$$

Commented by mathdanisur last updated on 18/Aug/21

$$\mathrm{Thank}\mathrm{you}\mathrm{Ser}$$$$\mathrm{what}\mathrm{an}\mathrm{inequality}\mathrm{it}\mathrm{was}\mathrm{please}$$

Commented by Ari last updated on 20/Aug/21

$$\mathrm{Can}\mathrm{you}\mathrm{explain}\mathrm{please}\mathrm{how}\mathrm{thid}\mathrm{inequality}\mathrm{is}?$$

Commented by Ari last updated on 20/Aug/21

$$\mathrm{Could}\mathrm{you}\mathrm{explain}\mathrm{please}\mathrm{how}\mathrm{this}\mathrm{enequality}\mathrm{is}?$$

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