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Question Number 84785 by john santu last updated on 16/Mar/20

at what time is the short clock   and long hour hand form an   angle of 180 degrees?

atwhattimeistheshortclockandlonghourhandformanangleof180degrees?

Commented by mr W last updated on 16/Mar/20

hour and minute hand?

hourandminutehand?

Commented by john santu last updated on 16/Mar/20

yes .

yes.

Answered by mr W last updated on 16/Mar/20

at 0:00h both hands are at position  θ=0.    at time h hour and m minute, the position of  minute hand is  θ_m =m  the position of hour hand is  θ_h =(h+(m/(60)))×5=5h+(m/(12))    when both hands form an angle of  180°, it means  ∣θ_m −θ_h ∣=30  m−5h−(m/(12))=±30  ((11m)/(12))−5h=±30  ⇒11m−60h=±360    for 11m−60h=360  ⇒m=((60(h+6))/(11))≤60 ⇒h≤5  h=0⇒time 0^h 32^m 43^s   h=1⇒time 1^h 38^m 10^s   h=2⇒time 2^h 43^m 38^s   h=3⇒time 3^h 49^m 05^s   h=4⇒time 4^h 54^m 32^s   h=5⇒time 5^h 60^m 00^s ⇒6^h 00^m 00^s     for 11m−60h=−360  ⇒m=((60(h−6))/(11))≥0 ⇒h≥6  h=6⇒time 6^h 00^m 00^s   h=7⇒time 7^h 05^m 27^s   h=8⇒time 8^h 10^m 54^s   h=9⇒time 9^h 16^m 21^s   h=10⇒time 10^h 21^m 49^s   h=11⇒time 11^h 27^m 16^s   h=12⇒time 12^h 32^m 43^s

at0:00hbothhandsareatpositionθ=0.attimehhourandmminute,thepositionofminutehandisθm=mthepositionofhourhandisθh=(h+m60)×5=5h+m12whenbothhandsformanangleof180°,itmeansθmθh∣=30m5hm12=±3011m125h=±3011m60h=±360for11m60h=360m=60(h+6)1160h5h=0time0h32m43sh=1time1h38m10sh=2time2h43m38sh=3time3h49m05sh=4time4h54m32sh=5time5h60m00s6h00m00sfor11m60h=360m=60(h6)110h6h=6time6h00m00sh=7time7h05m27sh=8time8h10m54sh=9time9h16m21sh=10time10h21m49sh=11time11h27m16sh=12time12h32m43s

Commented by john santu last updated on 16/Mar/20

waw great sir.  i find with my formula  θ_h  = for hour  θ_m  = for minute  the angle α = ∣30×θ_h −((11)/2)×θ_m ∣^(o )   if < 180^o   and β = 180^o −α , if > 180^o

wawgreatsir.ifindwithmyformulaθh=forhourθm=forminutetheangleα=30×θh112×θmoif<180oandβ=180oα,if>180o

Commented by mr W last updated on 16/Mar/20

the calculated instants are theoretic,  based on the assumption that the hands  move continuously. in reality the  hands of a classic mechanic clock  don′t move continuously. for example,  the second hand moves a step every  second, the minute hand moves a step  every 60 seconds, the hour hand moves  a step every 12 minutes. when we   consider this effect, we′ll get very  different and interesting things.  see Q17449 for example.

thecalculatedinstantsaretheoretic,basedontheassumptionthatthehandsmovecontinuously.inrealitythehandsofaclassicmechanicclockdontmovecontinuously.forexample,thesecondhandmovesastepeverysecond,theminutehandmovesastepevery60seconds,thehourhandmovesastepevery12minutes.whenweconsiderthiseffect,wellgetverydifferentandinterestingthings.seeQ17449forexample.

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