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Question Number 120469 by mathocean1 last updated on 31/Oct/20
calculatetherestofthedivisionof2nby3;n∈N
Answered by mathmax by abdo last updated on 31/Oct/20
n=2k⇒2n=22k=4kwehsve4≈1[3]⇒4n≈1[3]⇒r=1n=2k+1⇒2n=22k+1=2.4kwehave4k≈1[3]⇒2.4k≈2[3]⇒⇒r=2
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