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Question Number 62879 by mathmax by abdo last updated on 26/Jun/19

$$calculatemin\sum _{0⩽i⩽nand0⩽j⩽n}(i+j)$$

Answered by mr W last updated on 26/Jun/19

$$\sum _{0⩽i⩽nand0⩽j⩽n}(i+j)$$$$=\sum _{0⩽i⩽n}\sum _{0⩽j⩽n}(i+j)$$$$=\sum _{0⩽i⩽n}(i+\frac{n(1+n)}{2})$$$$=\frac{n(n+1)}{2}+\frac{n(1+n)}{2}$$$$=n(n+1)$$

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