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Question Number 20383 by tammi last updated on 26/Aug/17
∫dxx2+(x)13
Answered by $@ty@m last updated on 26/Aug/17
let2+x13=t2⇒x=(t2−2)3⇒dx=6(t2−2)2tdt∴thegivenintegral∫6(t2−2)2tdt(t2−2)3t=6∫dtt2−2=622ln∣t−2t+2∣+C
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