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Question Number 189886 by mnjuly1970 last updated on 23/Mar/23

e^( x) > 1+ x (∀ x >0 ) set: x=(√(π/e)) −1 e^( ((√π)/( (√e))) −1) > ((√π)/( (√e))) ⇒ e^( ((√π)/( (√e)))) > (√π) ( e^( ((√π)/( (√e)))) )^( (√e)) > (√π)^( (√e)) ⇒ e^( (√π)) > (√(π ))^( (√e))

ex>1+x(∀x>0)set:x=πe−1eπe−1>πe⇒eπe>π(eπe)e>πe⇒eπ>πe

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