f′(x)={_(3 ;x>2) ^(2x ; x≤2) f(2)=1 ise f(1)+f(3)=? czm∵ f(x)={_(3x+c_2 ; x>2) ^(x^2 +c_1 ;x≤2) f(2)=x^2 +c_1 dir 1=4+c_1 => c_1 =−3 1=2.3+c_2 => c_2 =−5 f(x)={_(3x−5 x>2) ^(x^2 −3 ;x≤2) f(1)=1^2 −3=−2, f(3)=3.3−5=4 f(1)+f(3)=−2+4=2


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Question Number 11899 by ahmet last updated on 04/Apr/17
$f′(x)={_(3 ;x>2) ^(2x ; x≤2) f(2)=1 ise f(1)+f(3)=? czm∵ f(x)={_(3x+c_2 ; x>2) ^(x^2 +c_1 ;x≤2) f(2)=x^2 +c_1 dir 1=4+c_1 => c_1 =−3 1=2.3+c_2 => c_2 =−5 f(x)={_(3x−5 x>2) ^(x^2 −3 ;x≤2) f(1)=1^2 −3=−2, f(3)=3.3−5=4 f(1)+f(3)=−2+4=2$
$f^{'} (x) = {_{3; x > 2}^{2 x; x ⩽ 2}$ $f (2) = 1 i s e f (1) + f (3) = ?$ $c z m ∵ f (x) = {_{3 x + c_{2}; x > 2}^{x^{2} + c_{1}; x ⩽ 2}$ $f (2) = x^{2} + c_{1} d i r$ $1 = 4 + c_{1} => c_{1} = - 3$ $1 = 2.3 + c_{2} => c_{2} = - 5$ $f (x) = {_{3 x - 5 x > 2}^{x^{2} - 3; x ⩽ 2}$ $f (1) = 1^{2} - 3 = - 2, f (3) = 3.3 - 5 = 4$ $f (1) + f (3) = - 2 + 4 = 2$
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