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Question Number 206882 by efronzo1 last updated on 29/Apr/24
f(x)=tan2xtanxtanxtanxtanx...543f′(π4)=?
Answered by MM42 last updated on 29/Apr/24
f(x)=tan2x×tan12x×tan16x×tan124×tan1120×...=(tanx)2+12+16+124+...+1n!+...=(tanx)e⇒f′(x)=e(tanx)e−1×(1+tan2x)⇒f′(π4)=2e✓
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