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Question Number 10415 by okhema francis last updated on 08/Feb/17

$$findallthepossiblevaluesof\cos \theta suchthat2\cot {}^2\theta +\cos \theta =0$$$$$$

Answered by bansal22luvi@gmail.com last updated on 08/Feb/17

$$2\left(\frac{{\cos }^2\theta }{{\sin }^2\theta }\right)+\cos \theta =0$$$${2\cos }^2\theta +\cos \theta {\sin }^2\theta =0$$$$\cos \theta (2\cos \theta +{\sin }^2\theta )=0$$$$\cos \theta =0$$$$2\cos \theta +{\sin }^2\theta =0$$$$2\cos \theta +1-{\cos }^2\theta =0$$$${\cos }^2\theta -2\cos \theta -1=0$$$$\cos \theta =\frac{2\pm 2\sqrt{2}}{2}$$$$\mathrm{hence}\cos \theta =0,\frac{1\pm \sqrt{2}}{}$$

Commented by okhema francis last updated on 09/Feb/17

$$thankyouverymuchandletthelordbewithyou$$

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