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Question Number 69764 by Rio Michael last updated on 27/Sep/19
finddydxifx=sin2tandy=tantatt=π4
Commented by kaivan.ahmadi last updated on 27/Sep/19
dydx=dydtdxdt=1+tan2tsin2t
Answered by mind is power last updated on 27/Sep/19
dydx=dydt.dtdx=dydt.(dxdt)−1=(1+tg2(t)).(sin(2t))−1∣t=π4=2.1−1=2
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