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Question Number 65776 by mathmax by abdo last updated on 03/Aug/19

$$find{\int }_{-\frac{\pi }{4}}^{\frac{\pi }{4}}\frac{cosx}{2+5sinx}dx$$

Commented by kaivan.ahmadi last updated on 04/Aug/19

$$u=2+5sinx\Rightarrow du=5cosxdx$$$$\frac{1}{5}\int \frac{du}{u}=\frac{1}{5}lnu=\frac{1}{5}ln(2+5sinx){\mid }_{-\frac{\pi }{4}}^{\frac{\pi }{4}}=$$

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