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Question Number 34282 by math khazana by abdo last updated on 03/May/18

find  ∫_(π/6) ^(π/3)       (dx/(cos(x) sin(x)))

findπ6π3dxcos(x)sin(x)

Commented by math khazana by abdo last updated on 07/May/18

I  = ∫_(π/6) ^(π/3)  2    (dx/(sin(2x))) = 2 ∫_(π/6) ^(π/3)     (dx/(sin(2x)))  =2[ (1/2)ln∣tanx∣]_(π/6) ^(π/3)   =ln(tan((π/3))) −ln(tan((π/6)))  = ln((√3) ) −ln((1/(√3))) = 2ln((√3)) = ln(3).

I=π6π32dxsin(2x)=2π6π3dxsin(2x)=2[12lntanx]π6π3=ln(tan(π3))ln(tan(π6))=ln(3)ln(13)=2ln(3)=ln(3).

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