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Question Number 170297 by ali009 last updated on 19/May/22
findthetotalchargeenclosedinsideavolumeof1.5×10−9locatedattheoriginifD=e−xsin(y)a^x−(e−xcos(y))a^y+2zaz^C/m2
Answered by ali009 last updated on 20/May/22
pv=▽.D→pv=−e−xsin(y)+e−xsin(y)+2=2Qenc=∫vpv.dvQenc=pv∫dvQenc=pv.v=1.5×10−9×2=3nC
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