find the value of Σ_(n=1) ^(n=∝) 1/_(n^2 (n+1)) we give Σ_(n=1) ^(n=∝) 1/_n 2= π^2 /6 and H_n =1+2^(−1) +3^(−1) +...+n^(−1) = ln(n) + s + θ(1/n) s is the constant number of Euler


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Question Number 25962 by abdo imad last updated on 16/Dec/17

$f i n d t h e v a l u e o f \sum_{n = 1}^{n =\propto} 1 /_{n^{2} (n + 1)} w e g i v e \sum_{n = 1}^{n =\propto} 1 /_{n} 2 = π^{2} / 6$ $a n d H_{n} = 1 + 2^{- 1} + 3^{- 1} + . . . + n^{- 1} = l n (n) + s + θ (1 / n)$ $s i s t h e c o n s t a n t n u m b e r o f E u l e r$
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