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Question Number 103294 by bramlex last updated on 14/Jul/20

$$\mathrm{from}\mathrm{letters}\mathrm{in}$$$${}^{\prime }{\mathrm{MATEMATIKA}}^{\prime }\mathrm{words}$$$$\mathrm{formed}\mathrm{by}\mathrm{using}\mathrm{all}\mathrm{the}\mathrm{letters}.$$$$\mathrm{How}\mathrm{many}\mathrm{words}\mathrm{that}\mathrm{can}\mathrm{be}$$$$\mathrm{formed}\mathrm{with}\mathrm{the}\mathrm{five}\mathrm{consonant}$$$$\mathrm{are}\mathrm{always}\mathrm{side}\mathrm{by}\mathrm{side}$$

Answered by bemath last updated on 14/Jul/20

$$\Rightarrow \frac{5!}{2!.2!.1!}\times \frac{6!}{3!.1!.1!}=$$$$\frac{120}{4}\times \frac{6.5.4.3!}{3!}=30\times 120=3600$$

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