given that the point (t^� ,0) lies on the curve y=2x^2 −x. find the value of t.


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Question Number 32794 by Rio Mike last updated on 02/Apr/18

$g i v e n t h a t t h e p o i n t (\bar{t}, 0) l i e s o n t h e$ $c u r v e y = 2 x^{2} - x . f i n d t h e v a l u e o f t .$
	Answered by Joel578 last updated on 02/Apr/18

	$y = 2 x^{2} - x$ $0 = 2 t^{2} - t$ $t (2 t - 1) = 0$ $t = 0 \lor t = \frac{1}{2}$
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