help please. A river is 5m wide and flows at 3.0ms^(−1) . A man can swim at 2.0ms^(−1) in still water. if he sets off at an angle of 90° to the bank calculate a) the mans time and velocity b) his distance downstream from the starting point till when he reaches the other side of the river bank c) the actual distance he swims through the water.


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Question Number 69207 by Rio Michael last updated on 21/Sep/19

$h e l p p l e a s e .$ $A r i v e r i s 5 m w i d e a n d f l o w s a t 3.0 {m s}^{- 1} . A m a n c a n s w i m a t 2.0 {m s}^{- 1}$ $i n s t i l l w a t e r . i f h e s e t s o f f a t a n a n g l e o f 90 ° t o t h e b a n k$ $c a l c u l a t e$ $a) t h e m a n s t i m e a n d v e l o c i t y$ $b) h i s d i s t a n c e d o w n s t r e a m f r o m t h e s t a r t i n g p o i n t t i l l$ $w h e n h e r e a c h e s t h e o t h e r s i d e o f t h e r i v e r b a n k$ $c) t h e a c t u a l d i s t a n c e h e s w i m s t h r o u g h t h e w a t e r .$
Commented by mr W last updated on 21/Sep/19

$w h e n t h e r i v e r i s o n l y 5 m w i d e, i^{'} l l$ $t r y t o j u m p t o t h e o t h e r s i d e d i r e c t l y$ $i n s t e a d o f s w i m .$
Commented by Rio Michael last updated on 21/Sep/19

$l o l m a n i t s j u s t a q u e s t i o n$
Commented by Prithwish sen last updated on 21/Sep/19

$ha ha ha! Yes mr . W sir I agree with you .$
	Answered by mr W last updated on 21/Sep/19

	$a)$ $t = \frac{5}{2} = 2.5 s e c$ $v = \sqrt{2^{2} + 3^{2}} = \sqrt{13} m / s$ $b)$ $2.5 \times 3 = 7.5 m$ $c)$ $\sqrt{5^{2} + 7 . 5^{2}} = \frac{5 \sqrt{13}}{2} \approx 9 m$
	Commented by Rio Michael last updated on 21/Sep/19

	$t h a n k s s i r$
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